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x^2+18-13.5x=0
a = 1; b = -13.5; c = +18;
Δ = b2-4ac
Δ = -13.52-4·1·18
Δ = 110.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13.5)-\sqrt{110.25}}{2*1}=\frac{13.5-\sqrt{110.25}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13.5)+\sqrt{110.25}}{2*1}=\frac{13.5+\sqrt{110.25}}{2} $
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